City W and City X are 528 km apart. At 6.24 p.m., Jenson is travelling at a uniform speed left City W for City X while Wesley set off from City X to City W along the same road at a uniform speed, which was 6 km/h slower than that of Jenson. The two met at 10.24 p.m.
- Find the speed of Jenson.
- If Wesley continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Jenson and Wesley to travel from 6.24 p.m. to 10.24 p.m. = 4 h
Average speed of Jenson and Wesley
= 528 ÷ 4
= 132 km/h
Jenson's speed
= (132 + 6) ÷ 2
= 138 ÷ 2
= 69 km/h
(b)
Wesley's speed
= 69 - 6
= 63 km/h
Distance that Wesley travelled in 4 h
= 4 x 63
= 252 km
Remaining distance that Wesley needed to travel
= 528 - 252
= 276 km
Time that Wesley needed to reach his destination after the two met
= 276 ÷ 63
= 4
2463 = 4
821 h
Answer(s): (a) 69 km/h; (b) 4
821 h