City U and City V are 576 km apart. At 4.14 p.m., Vincent is travelling at a uniform speed left City U for City V while Cody set off from City V to City U along the same road at a uniform speed, which was 8 km/h slower than that of Vincent. The two met at 8.14 p.m.
- Find the speed of Vincent.
- If Cody continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Vincent and Cody to travel from 4.14 p.m. to 8.14 p.m. = 4 h
Average speed of Vincent and Cody
= 576 ÷ 4
= 144 km/h
Vincent's speed
= (144 + 8) ÷ 2
= 152 ÷ 2
= 76 km/h
(b)
Cody's speed
= 76 - 8
= 68 km/h
Distance that Cody travelled in 4 h
= 4 x 68
= 272 km
Remaining distance that Cody needed to travel
= 576 - 272
= 304 km
Time that Cody needed to reach his destination after the two met
= 304 ÷ 68
= 4
3268 = 4
817 h
Answer(s): (a) 76 km/h; (b) 4
817 h