City Q and City R are 484 km apart. At 5.41 p.m., Paul is travelling at a uniform speed left City Q for City R while Flynn set off from City R to City Q along the same road at a uniform speed, which was 11 km/h slower than that of Paul. The two met at 9.41 p.m.
- Find the speed of Paul.
- If Flynn continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Paul and Flynn to travel from 5.41 p.m. to 9.41 p.m. = 4 h
Average speed of Paul and Flynn
= 484 ÷ 4
= 121 km/h
Paul's speed
= (121 + 11) ÷ 2
= 132 ÷ 2
= 66 km/h
(b)
Flynn's speed
= 66 - 11
= 55 km/h
Distance that Flynn travelled in 4 h
= 4 x 55
= 220 km
Remaining distance that Flynn needed to travel
= 484 - 220
= 264 km
Time that Flynn needed to reach his destination after the two met
= 264 ÷ 55
= 4
4455 = 4
45 h
Answer(s): (a) 66 km/h; (b) 4
45 h