City U and City V are 339 km apart. At 5.29 p.m., Charlie is travelling at a uniform speed left City U for City V while Tommy set off from City V to City U along the same road at a uniform speed, which was 11 km/h slower than that of Charlie. The two met at 8.29 p.m.

1. Find the speed of Charlie.
2. If Tommy continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.

(a)
Time taken for Charlie and Tommy to travel from 5.29 p.m. to 8.29 p.m. = 3 h

Average speed of Charlie and Tommy
= 339 ÷ 3
= 113 km/h

Charlie's speed
= (113 + 11) ÷ 2
= 124 ÷ 2 
= 62 km/h

(b)
Tommy's speed
= 62 - 11
= 51 km/h

Distance that Tommy travelled in 3 h
= 3 x 51
= 153 km

Remaining distance that Tommy needed to travel
= 339 - 153
= 186 km

Time that Tommy needed to reach his destination after the two met
= 186 ÷ 51
= 3³³₅₁
= 3¹¹₁₇ h

Answer(s): (a) 62 km/h; (b) 3¹¹₁₇ h