City Q and City R are 376 km apart. At 3.19 p.m., Fred is travelling at a uniform speed left City Q for City R while Elijah set off from City R to City Q along the same road at a uniform speed, which was 12 km/h slower than that of Fred. The two met at 5.19 p.m.
- Find the speed of Fred.
- If Elijah continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Fred and Elijah to travel from 3.19 p.m. to 5.19 p.m. = 2 h
Average speed of Fred and Elijah
= 376 ÷ 2
= 188 km/h
Fred's speed
= (188 + 12) ÷ 2
= 200 ÷ 2
= 100 km/h
(b)
Elijah's speed
= 100 - 12
= 88 km/h
Distance that Elijah travelled in 2 h
= 2 x 88
= 176 km
Remaining distance that Elijah needed to travel
= 376 - 176
= 200 km
Time that Elijah needed to reach his destination after the two met
= 200 ÷ 88
= 2
2488 = 2
311 h
Answer(s): (a) 100 km/h; (b) 2
311 h