City H and City J are 528 km apart. At 1.33 p.m., Daniel is travelling at a uniform speed left City H for City J while Albert set off from City J to City H along the same road at a uniform speed, which was 6 km/h slower than that of Daniel. The two met at 5.33 p.m.
- Find the speed of Daniel.
- If Albert continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Daniel and Albert to travel from 1.33 p.m. to 5.33 p.m. = 4 h
Average speed of Daniel and Albert
= 528 ÷ 4
= 132 km/h
Daniel's speed
= (132 + 6) ÷ 2
= 138 ÷ 2
= 69 km/h
(b)
Albert's speed
= 69 - 6
= 63 km/h
Distance that Albert travelled in 4 h
= 4 x 63
= 252 km
Remaining distance that Albert needed to travel
= 528 - 252
= 276 km
Time that Albert needed to reach his destination after the two met
= 276 ÷ 63
= 4
2463 = 4
821 h
Answer(s): (a) 69 km/h; (b) 4
821 h