City Z and City A are 570 km apart. At 1.53 p.m., Nick is travelling at a uniform speed left City Z for City A while Charlie set off from City A to City Z along the same road at a uniform speed, which was 12 km/h slower than that of Nick. The two met at 6.53 p.m.
- Find the speed of Nick.
- If Charlie continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Nick and Charlie to travel from 1.53 p.m. to 6.53 p.m. = 5 h
Average speed of Nick and Charlie
= 570 ÷ 5
= 114 km/h
Nick's speed
= (114 + 12) ÷ 2
= 126 ÷ 2
= 63 km/h
(b)
Charlie's speed
= 63 - 12
= 51 km/h
Distance that Charlie travelled in 5 h
= 5 x 51
= 255 km
Remaining distance that Charlie needed to travel
= 570 - 255
= 315 km
Time that Charlie needed to reach his destination after the two met
= 315 ÷ 51
= 6
951 = 6
317 h
Answer(s): (a) 63 km/h; (b) 6
317 h