City F and City G are 568 km apart. At 5.27 p.m., Howard is travelling at a uniform speed left City F for City G while Vincent set off from City G to City F along the same road at a uniform speed, which was 6 km/h slower than that of Howard. The two met at 9.27 p.m.
- Find the speed of Howard.
- If Vincent continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Howard and Vincent to travel from 5.27 p.m. to 9.27 p.m. = 4 h
Average speed of Howard and Vincent
= 568 ÷ 4
= 142 km/h
Howard's speed
= (142 + 6) ÷ 2
= 148 ÷ 2
= 74 km/h
(b)
Vincent's speed
= 74 - 6
= 68 km/h
Distance that Vincent travelled in 4 h
= 4 x 68
= 272 km
Remaining distance that Vincent needed to travel
= 568 - 272
= 296 km
Time that Vincent needed to reach his destination after the two met
= 296 ÷ 68
= 4
2468 = 4
617 h
Answer(s): (a) 74 km/h; (b) 4
617 h