City E and City F are 564 km apart. At 2.29 p.m., Bryan is travelling at a uniform speed left City E for City F while Henry set off from City F to City E along the same road at a uniform speed, which was 9 km/h slower than that of Bryan. The two met at 6.29 p.m.
- Find the speed of Bryan.
- If Henry continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Bryan and Henry to travel from 2.29 p.m. to 6.29 p.m. = 4 h
Average speed of Bryan and Henry
= 564 ÷ 4
= 141 km/h
Bryan's speed
= (141 + 9) ÷ 2
= 150 ÷ 2
= 75 km/h
(b)
Henry's speed
= 75 - 9
= 66 km/h
Distance that Henry travelled in 4 h
= 4 x 66
= 264 km
Remaining distance that Henry needed to travel
= 564 - 264
= 300 km
Time that Henry needed to reach his destination after the two met
= 300 ÷ 66
= 4
3666 = 4
611 h
Answer(s): (a) 75 km/h; (b) 4
611 h