City M and City N are 378 km apart. At 5.33 p.m., Asher is travelling at a uniform speed left City M for City N while Oscar set off from City N to City M along the same road at a uniform speed, which was 6 km/h slower than that of Asher. The two met at 8.33 p.m.
- Find the speed of Asher.
- If Oscar continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Asher and Oscar to travel from 5.33 p.m. to 8.33 p.m. = 3 h
Average speed of Asher and Oscar
= 378 ÷ 3
= 126 km/h
Asher's speed
= (126 + 6) ÷ 2
= 132 ÷ 2
= 66 km/h
(b)
Oscar's speed
= 66 - 6
= 60 km/h
Distance that Oscar travelled in 3 h
= 3 x 60
= 180 km
Remaining distance that Oscar needed to travel
= 378 - 180
= 198 km
Time that Oscar needed to reach his destination after the two met
= 198 ÷ 60
= 3
1860 = 3
310 h
Answer(s): (a) 66 km/h; (b) 3
310 h