City G and City H are 426 km apart. At 4.29 p.m., Cody is travelling at a uniform speed left City G for City H while Elijah set off from City H to City G along the same road at a uniform speed, which was 10 km/h slower than that of Cody. The two met at 7.29 p.m.
- Find the speed of Cody.
- If Elijah continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Cody and Elijah to travel from 4.29 p.m. to 7.29 p.m. = 3 h
Average speed of Cody and Elijah
= 426 ÷ 3
= 142 km/h
Cody's speed
= (142 + 10) ÷ 2
= 152 ÷ 2
= 76 km/h
(b)
Elijah's speed
= 76 - 10
= 66 km/h
Distance that Elijah travelled in 3 h
= 3 x 66
= 198 km
Remaining distance that Elijah needed to travel
= 426 - 198
= 228 km
Time that Elijah needed to reach his destination after the two met
= 228 ÷ 66
= 3
3066 = 3
511 h
Answer(s): (a) 76 km/h; (b) 3
511 h