City X and City Y are 585 km apart. At 6.52 p.m., Brandon is travelling at a uniform speed left City X for City Y while Oliver set off from City Y to City X along the same road at a uniform speed, which was 9 km/h slower than that of Brandon. The two met at 11.52 p.m.

1. Find the speed of Brandon.
2. If Oliver continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.

(a)
Time taken for Brandon and Oliver to travel from 6.52 p.m. to 11.52 p.m. = 5 h

Average speed of Brandon and Oliver
= 585 ÷ 5
= 117 km/h

Brandon's speed
= (117 + 9) ÷ 2
= 126 ÷ 2 
= 63 km/h

(b)
Oliver's speed
= 63 - 9
= 54 km/h

Distance that Oliver travelled in 5 h
= 5 x 54
= 270 km

Remaining distance that Oliver needed to travel
= 585 - 270
= 315 km

Time that Oliver needed to reach his destination after the two met
= 315 ÷ 54
= 5⁴⁵₅₄
= 5⁵₆ h

Answer(s): (a) 63 km/h; (b) 5⁵₆ h