City S and City T are 357 km apart. At 5.14 p.m., Julian is travelling at a uniform speed left City S for City T while Asher set off from City T to City S along the same road at a uniform speed, which was 11 km/h slower than that of Julian. The two met at 8.14 p.m.
- Find the speed of Julian.
- If Asher continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Julian and Asher to travel from 5.14 p.m. to 8.14 p.m. = 3 h
Average speed of Julian and Asher
= 357 ÷ 3
= 119 km/h
Julian's speed
= (119 + 11) ÷ 2
= 130 ÷ 2
= 65 km/h
(b)
Asher's speed
= 65 - 11
= 54 km/h
Distance that Asher travelled in 3 h
= 3 x 54
= 162 km
Remaining distance that Asher needed to travel
= 357 - 162
= 195 km
Time that Asher needed to reach his destination after the two met
= 195 ÷ 54
= 3
3354 = 3
1118 h
Answer(s): (a) 65 km/h; (b) 3
1118 h