City L and City M are 560 km apart. At 5.23 p.m., Neave is travelling at a uniform speed left City L for City M while Warren set off from City M to City L along the same road at a uniform speed, which was 12 km/h slower than that of Neave. The two met at 10.23 p.m.

1. Find the speed of Neave.
2. If Warren continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.

(a)
Time taken for Neave and Warren to travel from 5.23 p.m. to 10.23 p.m. = 5 h

Average speed of Neave and Warren
= 560 ÷ 5
= 112 km/h

Neave's speed
= (112 + 12) ÷ 2
= 124 ÷ 2 
= 62 km/h

(b)
Warren's speed
= 62 - 12
= 50 km/h

Distance that Warren travelled in 5 h
= 5 x 50
= 250 km

Remaining distance that Warren needed to travel
= 560 - 250
= 310 km

Time that Warren needed to reach his destination after the two met
= 310 ÷ 50
= 6¹⁰₅₀
= 6¹₅ h

Answer(s): (a) 62 km/h; (b) 6¹₅ h