City S and City T are 528 km apart. At 6.43 p.m., Neave is travelling at a uniform speed left City S for City T while Ahmad set off from City T to City S along the same road at a uniform speed, which was 6 km/h slower than that of Neave. The two met at 10.43 p.m.

1. Find the speed of Neave.
2. If Ahmad continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.

(a)
Time taken for Neave and Ahmad to travel from 6.43 p.m. to 10.43 p.m. = 4 h

Average speed of Neave and Ahmad
= 528 ÷ 4
= 132 km/h

Neave's speed
= (132 + 6) ÷ 2
= 138 ÷ 2 
= 69 km/h

(b)
Ahmad's speed
= 69 - 6
= 63 km/h

Distance that Ahmad travelled in 4 h
= 4 x 63
= 252 km

Remaining distance that Ahmad needed to travel
= 528 - 252
= 276 km

Time that Ahmad needed to reach his destination after the two met
= 276 ÷ 63
= 4²⁴₆₃
= 4⁸₂₁ h

Answer(s): (a) 69 km/h; (b) 4⁸₂₁ h