City Q and City R are 594 km apart. At 1.39 p.m., Pierre is travelling at a uniform speed left City Q for City R while Jenson set off from City R to City Q along the same road at a uniform speed, which was 6 km/h slower than that of Pierre. The two met at 4.39 p.m.
- Find the speed of Pierre.
- If Jenson continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Pierre and Jenson to travel from 1.39 p.m. to 4.39 p.m. = 3 h
Average speed of Pierre and Jenson
= 594 ÷ 3
= 198 km/h
Pierre's speed
= (198 + 6) ÷ 2
= 204 ÷ 2
= 102 km/h
(b)
Jenson's speed
= 102 - 6
= 96 km/h
Distance that Jenson travelled in 3 h
= 3 x 96
= 288 km
Remaining distance that Jenson needed to travel
= 594 - 288
= 306 km
Time that Jenson needed to reach his destination after the two met
= 306 ÷ 96
= 3
1896 = 3
316 h
Answer(s): (a) 102 km/h; (b) 3
316 h