City Q and City R are 564 km apart. At 4.11 p.m., Owen is travelling at a uniform speed left City Q for City R while Wesley set off from City R to City Q along the same road at a uniform speed, which was 8 km/h slower than that of Owen. The two met at 7.11 p.m.
- Find the speed of Owen.
- If Wesley continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Owen and Wesley to travel from 4.11 p.m. to 7.11 p.m. = 3 h
Average speed of Owen and Wesley
= 564 ÷ 3
= 188 km/h
Owen's speed
= (188 + 8) ÷ 2
= 196 ÷ 2
= 98 km/h
(b)
Wesley's speed
= 98 - 8
= 90 km/h
Distance that Wesley travelled in 3 h
= 3 x 90
= 270 km
Remaining distance that Wesley needed to travel
= 564 - 270
= 294 km
Time that Wesley needed to reach his destination after the two met
= 294 ÷ 90
= 3
2490 = 3
415 h
Answer(s): (a) 98 km/h; (b) 3
415 h