City J and City K are 352 km apart. At 1.35 p.m., Zeph is travelling at a uniform speed left City J for City K while Vincent set off from City K to City J along the same road at a uniform speed, which was 8 km/h slower than that of Zeph. The two met at 3.35 p.m.
- Find the speed of Zeph.
- If Vincent continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Zeph and Vincent to travel from 1.35 p.m. to 3.35 p.m. = 2 h
Average speed of Zeph and Vincent
= 352 ÷ 2
= 176 km/h
Zeph's speed
= (176 + 8) ÷ 2
= 184 ÷ 2
= 92 km/h
(b)
Vincent's speed
= 92 - 8
= 84 km/h
Distance that Vincent travelled in 2 h
= 2 x 84
= 168 km
Remaining distance that Vincent needed to travel
= 352 - 168
= 184 km
Time that Vincent needed to reach his destination after the two met
= 184 ÷ 84
= 2
1684 = 2
421 h
Answer(s): (a) 92 km/h; (b) 2
421 h