City S and City T are 339 km apart. At 1.47 p.m., Reggie is travelling at a uniform speed left City S for City T while Fabian set off from City T to City S along the same road at a uniform speed, which was 11 km/h slower than that of Reggie. The two met at 4.47 p.m.
- Find the speed of Reggie.
- If Fabian continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Reggie and Fabian to travel from 1.47 p.m. to 4.47 p.m. = 3 h
Average speed of Reggie and Fabian
= 339 ÷ 3
= 113 km/h
Reggie's speed
= (113 + 11) ÷ 2
= 124 ÷ 2
= 62 km/h
(b)
Fabian's speed
= 62 - 11
= 51 km/h
Distance that Fabian travelled in 3 h
= 3 x 51
= 153 km
Remaining distance that Fabian needed to travel
= 339 - 153
= 186 km
Time that Fabian needed to reach his destination after the two met
= 186 ÷ 51
= 3
3351 = 3
1117 h
Answer(s): (a) 62 km/h; (b) 3
1117 h