City N and City P are 504 km apart. At 1.25 p.m., Ryan is travelling at a uniform speed left City N for City P while Brandon set off from City P to City N along the same road at a uniform speed, which was 6 km/h slower than that of Ryan. The two met at 5.25 p.m.
- Find the speed of Ryan.
- If Brandon continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Ryan and Brandon to travel from 1.25 p.m. to 5.25 p.m. = 4 h
Average speed of Ryan and Brandon
= 504 ÷ 4
= 126 km/h
Ryan's speed
= (126 + 6) ÷ 2
= 132 ÷ 2
= 66 km/h
(b)
Brandon's speed
= 66 - 6
= 60 km/h
Distance that Brandon travelled in 4 h
= 4 x 60
= 240 km
Remaining distance that Brandon needed to travel
= 504 - 240
= 264 km
Time that Brandon needed to reach his destination after the two met
= 264 ÷ 60
= 4
2460 = 4
25 h
Answer(s): (a) 66 km/h; (b) 4
25 h