City H and City J are 576 km apart. At 6.52 p.m., Vincent is travelling at a uniform speed left City H for City J while Owen set off from City J to City H along the same road at a uniform speed, which was 8 km/h slower than that of Vincent. The two met at 10.52 p.m.
- Find the speed of Vincent.
- If Owen continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Vincent and Owen to travel from 6.52 p.m. to 10.52 p.m. = 4 h
Average speed of Vincent and Owen
= 576 ÷ 4
= 144 km/h
Vincent's speed
= (144 + 8) ÷ 2
= 152 ÷ 2
= 76 km/h
(b)
Owen's speed
= 76 - 8
= 68 km/h
Distance that Owen travelled in 4 h
= 4 x 68
= 272 km
Remaining distance that Owen needed to travel
= 576 - 272
= 304 km
Time that Owen needed to reach his destination after the two met
= 304 ÷ 68
= 4
3268 = 4
817 h
Answer(s): (a) 76 km/h; (b) 4
817 h