City S and City T are 465 km apart. At 4.28 p.m., Zane is travelling at a uniform speed left City S for City T while Paul set off from City T to City S along the same road at a uniform speed, which was 5 km/h slower than that of Zane. The two met at 7.28 p.m.

1. Find the speed of Zane.
2. If Paul continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.

(a)
Time taken for Zane and Paul to travel from 4.28 p.m. to 7.28 p.m. = 3 h

Average speed of Zane and Paul
= 465 ÷ 3
= 155 km/h

Zane's speed
= (155 + 5) ÷ 2
= 160 ÷ 2 
= 80 km/h

(b)
Paul's speed
= 80 - 5
= 75 km/h

Distance that Paul travelled in 3 h
= 3 x 75
= 225 km

Remaining distance that Paul needed to travel
= 465 - 225
= 240 km

Time that Paul needed to reach his destination after the two met
= 240 ÷ 75
= 3¹⁵₇₅
= 3¹₅ h

Answer(s): (a) 80 km/h; (b) 3¹₅ h