City Q and City R are 366 km apart. At 5.14 p.m., Cody is travelling at a uniform speed left City Q for City R while Caden set off from City R to City Q along the same road at a uniform speed, which was 8 km/h slower than that of Cody. The two met at 8.14 p.m.
- Find the speed of Cody.
- If Caden continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Cody and Caden to travel from 5.14 p.m. to 8.14 p.m. = 3 h
Average speed of Cody and Caden
= 366 ÷ 3
= 122 km/h
Cody's speed
= (122 + 8) ÷ 2
= 130 ÷ 2
= 65 km/h
(b)
Caden's speed
= 65 - 8
= 57 km/h
Distance that Caden travelled in 3 h
= 3 x 57
= 171 km
Remaining distance that Caden needed to travel
= 366 - 171
= 195 km
Time that Caden needed to reach his destination after the two met
= 195 ÷ 57
= 3
2457 = 3
819 h
Answer(s): (a) 65 km/h; (b) 3
819 h