City G and City H are 536 km apart. At 5.16 p.m., Lee is travelling at a uniform speed left City G for City H while Neave set off from City H to City G along the same road at a uniform speed, which was 6 km/h slower than that of Lee. The two met at 9.16 p.m.
- Find the speed of Lee.
- If Neave continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Lee and Neave to travel from 5.16 p.m. to 9.16 p.m. = 4 h
Average speed of Lee and Neave
= 536 ÷ 4
= 134 km/h
Lee's speed
= (134 + 6) ÷ 2
= 140 ÷ 2
= 70 km/h
(b)
Neave's speed
= 70 - 6
= 64 km/h
Distance that Neave travelled in 4 h
= 4 x 64
= 256 km
Remaining distance that Neave needed to travel
= 536 - 256
= 280 km
Time that Neave needed to reach his destination after the two met
= 280 ÷ 64
= 4
2464 = 4
38 h
Answer(s): (a) 70 km/h; (b) 4
38 h