City Y and City Z are 560 km apart. At 6.11 p.m., Zane is travelling at a uniform speed left City Y for City Z while Peter set off from City Z to City Y along the same road at a uniform speed, which was 10 km/h slower than that of Zane. The two met at 10.11 p.m.

1. Find the speed of Zane.
2. If Peter continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.

(a)
Time taken for Zane and Peter to travel from 6.11 p.m. to 10.11 p.m. = 4 h

Average speed of Zane and Peter
= 560 ÷ 4
= 140 km/h

Zane's speed
= (140 + 10) ÷ 2
= 150 ÷ 2 
= 75 km/h

(b)
Peter's speed
= 75 - 10
= 65 km/h

Distance that Peter travelled in 4 h
= 4 x 65
= 260 km

Remaining distance that Peter needed to travel
= 560 - 260
= 300 km

Time that Peter needed to reach his destination after the two met
= 300 ÷ 65
= 4⁴⁰₆₅
= 4⁸₁₃ h

Answer(s): (a) 75 km/h; (b) 4⁸₁₃ h