City U and City V are 484 km apart. At 5.27 p.m., Dylan is travelling at a uniform speed left City U for City V while Will set off from City V to City U along the same road at a uniform speed, which was 9 km/h slower than that of Dylan. The two met at 9.27 p.m.

1. Find the speed of Dylan.
2. If Will continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.

(a)
Time taken for Dylan and Will to travel from 5.27 p.m. to 9.27 p.m. = 4 h

Average speed of Dylan and Will
= 484 ÷ 4
= 121 km/h

Dylan's speed
= (121 + 9) ÷ 2
= 130 ÷ 2 
= 65 km/h

(b)
Will's speed
= 65 - 9
= 56 km/h

Distance that Will travelled in 4 h
= 4 x 56
= 224 km

Remaining distance that Will needed to travel
= 484 - 224
= 260 km

Time that Will needed to reach his destination after the two met
= 260 ÷ 56
= 4³⁶₅₆
= 4⁹₁₄ h

Answer(s): (a) 65 km/h; (b) 4⁹₁₄ h