City K and City L are 456 km apart. At 1.20 p.m., Owen is travelling at a uniform speed left City K for City L while Pierre set off from City L to City K along the same road at a uniform speed, which was 10 km/h slower than that of Owen. The two met at 5.20 p.m.
- Find the speed of Owen.
- If Pierre continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Owen and Pierre to travel from 1.20 p.m. to 5.20 p.m. = 4 h
Average speed of Owen and Pierre
= 456 ÷ 4
= 114 km/h
Owen's speed
= (114 + 10) ÷ 2
= 124 ÷ 2
= 62 km/h
(b)
Pierre's speed
= 62 - 10
= 52 km/h
Distance that Pierre travelled in 4 h
= 4 x 52
= 208 km
Remaining distance that Pierre needed to travel
= 456 - 208
= 248 km
Time that Pierre needed to reach his destination after the two met
= 248 ÷ 52
= 4
4052 = 4
1013 h
Answer(s): (a) 62 km/h; (b) 4
1013 h