City D and City E are 460 km apart. At 2.38 p.m., Andy is travelling at a uniform speed left City D for City E while Howard set off from City E to City D along the same road at a uniform speed, which was 10 km/h slower than that of Andy. The two met at 4.38 p.m.
- Find the speed of Andy.
- If Howard continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Andy and Howard to travel from 2.38 p.m. to 4.38 p.m. = 2 h
Average speed of Andy and Howard
= 460 ÷ 2
= 230 km/h
Andy's speed
= (230 + 10) ÷ 2
= 240 ÷ 2
= 120 km/h
(b)
Howard's speed
= 120 - 10
= 110 km/h
Distance that Howard travelled in 2 h
= 2 x 110
= 220 km
Remaining distance that Howard needed to travel
= 460 - 220
= 240 km
Time that Howard needed to reach his destination after the two met
= 240 ÷ 110
= 2
20110 = 2
211 h
Answer(s): (a) 120 km/h; (b) 2
211 h