City Z and City A are 396 km apart. At 1.48 p.m., Oscar is travelling at a uniform speed left City Z for City A while Wesley set off from City A to City Z along the same road at a uniform speed, which was 6 km/h slower than that of Oscar. The two met at 3.48 p.m.

1. Find the speed of Oscar.
2. If Wesley continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.

(a)
Time taken for Oscar and Wesley to travel from 1.48 p.m. to 3.48 p.m. = 2 h

Average speed of Oscar and Wesley
= 396 ÷ 2
= 198 km/h

Oscar's speed
= (198 + 6) ÷ 2
= 204 ÷ 2 
= 102 km/h

(b)
Wesley's speed
= 102 - 6
= 96 km/h

Distance that Wesley travelled in 2 h
= 2 x 96
= 192 km

Remaining distance that Wesley needed to travel
= 396 - 192
= 204 km

Time that Wesley needed to reach his destination after the two met
= 204 ÷ 96
= 2¹²₉₆
= 2¹₈ h

Answer(s): (a) 102 km/h; (b) 2¹₈ h