City J and City K are 540 km apart. At 6.59 p.m., Zane is travelling at a uniform speed left City J for City K while Caden set off from City K to City J along the same road at a uniform speed, which was 7 km/h slower than that of Zane. The two met at 10.59 p.m.
- Find the speed of Zane.
- If Caden continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Zane and Caden to travel from 6.59 p.m. to 10.59 p.m. = 4 h
Average speed of Zane and Caden
= 540 ÷ 4
= 135 km/h
Zane's speed
= (135 + 7) ÷ 2
= 142 ÷ 2
= 71 km/h
(b)
Caden's speed
= 71 - 7
= 64 km/h
Distance that Caden travelled in 4 h
= 4 x 64
= 256 km
Remaining distance that Caden needed to travel
= 540 - 256
= 284 km
Time that Caden needed to reach his destination after the two met
= 284 ÷ 64
= 4
2864 = 4
716 h
Answer(s): (a) 71 km/h; (b) 4
716 h