City D and City E are 368 km apart. At 4.19 p.m., Reggie is travelling at a uniform speed left City D for City E while Michael set off from City E to City D along the same road at a uniform speed, which was 8 km/h slower than that of Reggie. The two met at 6.19 p.m.
- Find the speed of Reggie.
- If Michael continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Reggie and Michael to travel from 4.19 p.m. to 6.19 p.m. = 2 h
Average speed of Reggie and Michael
= 368 ÷ 2
= 184 km/h
Reggie's speed
= (184 + 8) ÷ 2
= 192 ÷ 2
= 96 km/h
(b)
Michael's speed
= 96 - 8
= 88 km/h
Distance that Michael travelled in 2 h
= 2 x 88
= 176 km
Remaining distance that Michael needed to travel
= 368 - 176
= 192 km
Time that Michael needed to reach his destination after the two met
= 192 ÷ 88
= 2
1688 = 2
211 h
Answer(s): (a) 96 km/h; (b) 2
211 h