City W and City X are 480 km apart. At 2.18 p.m., Flynn is travelling at a uniform speed left City W for City X while Elijah set off from City X to City W along the same road at a uniform speed, which was 12 km/h slower than that of Flynn. The two met at 6.18 p.m.
- Find the speed of Flynn.
- If Elijah continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Flynn and Elijah to travel from 2.18 p.m. to 6.18 p.m. = 4 h
Average speed of Flynn and Elijah
= 480 ÷ 4
= 120 km/h
Flynn's speed
= (120 + 12) ÷ 2
= 132 ÷ 2
= 66 km/h
(b)
Elijah's speed
= 66 - 12
= 54 km/h
Distance that Elijah travelled in 4 h
= 4 x 54
= 216 km
Remaining distance that Elijah needed to travel
= 480 - 216
= 264 km
Time that Elijah needed to reach his destination after the two met
= 264 ÷ 54
= 4
4854 = 4
89 h
Answer(s): (a) 66 km/h; (b) 4
89 h