City U and City V are 360 km apart. At 5.59 p.m., Howard is travelling at a uniform speed left City U for City V while Caden set off from City V to City U along the same road at a uniform speed, which was 10 km/h slower than that of Howard. The two met at 7.59 p.m.
- Find the speed of Howard.
- If Caden continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Howard and Caden to travel from 5.59 p.m. to 7.59 p.m. = 2 h
Average speed of Howard and Caden
= 360 ÷ 2
= 180 km/h
Howard's speed
= (180 + 10) ÷ 2
= 190 ÷ 2
= 95 km/h
(b)
Caden's speed
= 95 - 10
= 85 km/h
Distance that Caden travelled in 2 h
= 2 x 85
= 170 km
Remaining distance that Caden needed to travel
= 360 - 170
= 190 km
Time that Caden needed to reach his destination after the two met
= 190 ÷ 85
= 2
2085 = 2
417 h
Answer(s): (a) 95 km/h; (b) 2
417 h