City N and City P are 344 km apart. At 3.45 p.m., Will is travelling at a uniform speed left City N for City P while Xavier set off from City P to City N along the same road at a uniform speed, which was 12 km/h slower than that of Will. The two met at 5.45 p.m.
- Find the speed of Will.
- If Xavier continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Will and Xavier to travel from 3.45 p.m. to 5.45 p.m. = 2 h
Average speed of Will and Xavier
= 344 ÷ 2
= 172 km/h
Will's speed
= (172 + 12) ÷ 2
= 184 ÷ 2
= 92 km/h
(b)
Xavier's speed
= 92 - 12
= 80 km/h
Distance that Xavier travelled in 2 h
= 2 x 80
= 160 km
Remaining distance that Xavier needed to travel
= 344 - 160
= 184 km
Time that Xavier needed to reach his destination after the two met
= 184 ÷ 80
= 2
2480 = 2
310 h
Answer(s): (a) 92 km/h; (b) 2
310 h