City J and City K are 462 km apart. At 2.18 p.m., Brandon is travelling at a uniform speed left City J for City K while Zane set off from City K to City J along the same road at a uniform speed, which was 10 km/h slower than that of Brandon. The two met at 5.18 p.m.
- Find the speed of Brandon.
- If Zane continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Brandon and Zane to travel from 2.18 p.m. to 5.18 p.m. = 3 h
Average speed of Brandon and Zane
= 462 ÷ 3
= 154 km/h
Brandon's speed
= (154 + 10) ÷ 2
= 164 ÷ 2
= 82 km/h
(b)
Zane's speed
= 82 - 10
= 72 km/h
Distance that Zane travelled in 3 h
= 3 x 72
= 216 km
Remaining distance that Zane needed to travel
= 462 - 216
= 246 km
Time that Zane needed to reach his destination after the two met
= 246 ÷ 72
= 3
3072 = 3
512 h
Answer(s): (a) 82 km/h; (b) 3
512 h