City U and City V are 356 km apart. At 2.24 p.m., Henry is travelling at a uniform speed left City U for City V while Brandon set off from City V to City U along the same road at a uniform speed, which was 10 km/h slower than that of Henry. The two met at 4.24 p.m.
- Find the speed of Henry.
- If Brandon continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Henry and Brandon to travel from 2.24 p.m. to 4.24 p.m. = 2 h
Average speed of Henry and Brandon
= 356 ÷ 2
= 178 km/h
Henry's speed
= (178 + 10) ÷ 2
= 188 ÷ 2
= 94 km/h
(b)
Brandon's speed
= 94 - 10
= 84 km/h
Distance that Brandon travelled in 2 h
= 2 x 84
= 168 km
Remaining distance that Brandon needed to travel
= 356 - 168
= 188 km
Time that Brandon needed to reach his destination after the two met
= 188 ÷ 84
= 2
2084 = 2
521 h
Answer(s): (a) 94 km/h; (b) 2
521 h