City U and City V are 552 km apart. At 1.12 p.m., Howard is travelling at a uniform speed left City U for City V while Ivan set off from City V to City U along the same road at a uniform speed, which was 8 km/h slower than that of Howard. The two met at 4.12 p.m.
- Find the speed of Howard.
- If Ivan continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Howard and Ivan to travel from 1.12 p.m. to 4.12 p.m. = 3 h
Average speed of Howard and Ivan
= 552 ÷ 3
= 184 km/h
Howard's speed
= (184 + 8) ÷ 2
= 192 ÷ 2
= 96 km/h
(b)
Ivan's speed
= 96 - 8
= 88 km/h
Distance that Ivan travelled in 3 h
= 3 x 88
= 264 km
Remaining distance that Ivan needed to travel
= 552 - 264
= 288 km
Time that Ivan needed to reach his destination after the two met
= 288 ÷ 88
= 3
2488 = 3
311 h
Answer(s): (a) 96 km/h; (b) 3
311 h