City S and City T are 552 km apart. At 6.35 p.m., Dylan is travelling at a uniform speed left City S for City T while Jenson set off from City T to City S along the same road at a uniform speed, which was 8 km/h slower than that of Dylan. The two met at 9.35 p.m.
- Find the speed of Dylan.
- If Jenson continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Dylan and Jenson to travel from 6.35 p.m. to 9.35 p.m. = 3 h
Average speed of Dylan and Jenson
= 552 ÷ 3
= 184 km/h
Dylan's speed
= (184 + 8) ÷ 2
= 192 ÷ 2
= 96 km/h
(b)
Jenson's speed
= 96 - 8
= 88 km/h
Distance that Jenson travelled in 3 h
= 3 x 88
= 264 km
Remaining distance that Jenson needed to travel
= 552 - 264
= 288 km
Time that Jenson needed to reach his destination after the two met
= 288 ÷ 88
= 3
2488 = 3
311 h
Answer(s): (a) 96 km/h; (b) 3
311 h