City F and City G are 432 km apart. At 2.38 p.m., Reggie is travelling at a uniform speed left City F for City G while Dylan set off from City G to City F along the same road at a uniform speed, which was 8 km/h slower than that of Reggie. The two met at 5.38 p.m.
- Find the speed of Reggie.
- If Dylan continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Reggie and Dylan to travel from 2.38 p.m. to 5.38 p.m. = 3 h
Average speed of Reggie and Dylan
= 432 ÷ 3
= 144 km/h
Reggie's speed
= (144 + 8) ÷ 2
= 152 ÷ 2
= 76 km/h
(b)
Dylan's speed
= 76 - 8
= 68 km/h
Distance that Dylan travelled in 3 h
= 3 x 68
= 204 km
Remaining distance that Dylan needed to travel
= 432 - 204
= 228 km
Time that Dylan needed to reach his destination after the two met
= 228 ÷ 68
= 3
2468 = 3
617 h
Answer(s): (a) 76 km/h; (b) 3
617 h