City Q and City R are 486 km apart. At 2.24 p.m., Jeremy is travelling at a uniform speed left City Q for City R while Cody set off from City R to City Q along the same road at a uniform speed, which was 6 km/h slower than that of Jeremy. The two met at 5.24 p.m.
- Find the speed of Jeremy.
- If Cody continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Jeremy and Cody to travel from 2.24 p.m. to 5.24 p.m. = 3 h
Average speed of Jeremy and Cody
= 486 ÷ 3
= 162 km/h
Jeremy's speed
= (162 + 6) ÷ 2
= 168 ÷ 2
= 84 km/h
(b)
Cody's speed
= 84 - 6
= 78 km/h
Distance that Cody travelled in 3 h
= 3 x 78
= 234 km
Remaining distance that Cody needed to travel
= 486 - 234
= 252 km
Time that Cody needed to reach his destination after the two met
= 252 ÷ 78
= 3
1878 = 3
313 h
Answer(s): (a) 84 km/h; (b) 3
313 h