City T and City U are 528 km apart. At 6.49 p.m., Cole is travelling at a uniform speed left City T for City U while Reggie set off from City U to City T along the same road at a uniform speed, which was 8 km/h slower than that of Cole. The two met at 9.49 p.m.
- Find the speed of Cole.
- If Reggie continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Cole and Reggie to travel from 6.49 p.m. to 9.49 p.m. = 3 h
Average speed of Cole and Reggie
= 528 ÷ 3
= 176 km/h
Cole's speed
= (176 + 8) ÷ 2
= 184 ÷ 2
= 92 km/h
(b)
Reggie's speed
= 92 - 8
= 84 km/h
Distance that Reggie travelled in 3 h
= 3 x 84
= 252 km
Remaining distance that Reggie needed to travel
= 528 - 252
= 276 km
Time that Reggie needed to reach his destination after the two met
= 276 ÷ 84
= 3
2484 = 3
27 h
Answer(s): (a) 92 km/h; (b) 3
27 h