City L and City M are 580 km apart. At 5.26 p.m., Ryan is travelling at a uniform speed left City L for City M while Michael set off from City M to City L along the same road at a uniform speed, which was 12 km/h slower than that of Ryan. The two met at 10.26 p.m.
- Find the speed of Ryan.
- If Michael continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Ryan and Michael to travel from 5.26 p.m. to 10.26 p.m. = 5 h
Average speed of Ryan and Michael
= 580 ÷ 5
= 116 km/h
Ryan's speed
= (116 + 12) ÷ 2
= 128 ÷ 2
= 64 km/h
(b)
Michael's speed
= 64 - 12
= 52 km/h
Distance that Michael travelled in 5 h
= 5 x 52
= 260 km
Remaining distance that Michael needed to travel
= 580 - 260
= 320 km
Time that Michael needed to reach his destination after the two met
= 320 ÷ 52
= 6
852 = 6
213 h
Answer(s): (a) 64 km/h; (b) 6
213 h