City S and City T are 544 km apart. At 6.52 p.m., Neave is travelling at a uniform speed left City S for City T while Howard set off from City T to City S along the same road at a uniform speed, which was 8 km/h slower than that of Neave. The two met at 10.52 p.m.
- Find the speed of Neave.
- If Howard continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Neave and Howard to travel from 6.52 p.m. to 10.52 p.m. = 4 h
Average speed of Neave and Howard
= 544 ÷ 4
= 136 km/h
Neave's speed
= (136 + 8) ÷ 2
= 144 ÷ 2
= 72 km/h
(b)
Howard's speed
= 72 - 8
= 64 km/h
Distance that Howard travelled in 4 h
= 4 x 64
= 256 km
Remaining distance that Howard needed to travel
= 544 - 256
= 288 km
Time that Howard needed to reach his destination after the two met
= 288 ÷ 64
= 4
3264 = 4
12 h
Answer(s): (a) 72 km/h; (b) 4
12 h