City Y and City Z are 495 km apart. At 1.42 p.m., Harry is travelling at a uniform speed left City Y for City Z while Asher set off from City Z to City Y along the same road at a uniform speed, which was 5 km/h slower than that of Harry. The two met at 4.42 p.m.
- Find the speed of Harry.
- If Asher continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Harry and Asher to travel from 1.42 p.m. to 4.42 p.m. = 3 h
Average speed of Harry and Asher
= 495 ÷ 3
= 165 km/h
Harry's speed
= (165 + 5) ÷ 2
= 170 ÷ 2
= 85 km/h
(b)
Asher's speed
= 85 - 5
= 80 km/h
Distance that Asher travelled in 3 h
= 3 x 80
= 240 km
Remaining distance that Asher needed to travel
= 495 - 240
= 255 km
Time that Asher needed to reach his destination after the two met
= 255 ÷ 80
= 3
1580 = 3
316 h
Answer(s): (a) 85 km/h; (b) 3
316 h