City A and City B are 351 km apart. At 4.36 p.m., Michael is travelling at a uniform speed left City A for City B while Pierre set off from City B to City A along the same road at a uniform speed, which was 9 km/h slower than that of Michael. The two met at 7.36 p.m.
- Find the speed of Michael.
- If Pierre continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Michael and Pierre to travel from 4.36 p.m. to 7.36 p.m. = 3 h
Average speed of Michael and Pierre
= 351 ÷ 3
= 117 km/h
Michael's speed
= (117 + 9) ÷ 2
= 126 ÷ 2
= 63 km/h
(b)
Pierre's speed
= 63 - 9
= 54 km/h
Distance that Pierre travelled in 3 h
= 3 x 54
= 162 km
Remaining distance that Pierre needed to travel
= 351 - 162
= 189 km
Time that Pierre needed to reach his destination after the two met
= 189 ÷ 54
= 3
2754 = 3
12 h
Answer(s): (a) 63 km/h; (b) 3
12 h