City R and City S are 339 km apart. At 3.25 p.m., Gabriel is travelling at a uniform speed left City R for City S while Tom set off from City S to City R along the same road at a uniform speed, which was 11 km/h slower than that of Gabriel. The two met at 6.25 p.m.
- Find the speed of Gabriel.
- If Tom continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Gabriel and Tom to travel from 3.25 p.m. to 6.25 p.m. = 3 h
Average speed of Gabriel and Tom
= 339 ÷ 3
= 113 km/h
Gabriel's speed
= (113 + 11) ÷ 2
= 124 ÷ 2
= 62 km/h
(b)
Tom's speed
= 62 - 11
= 51 km/h
Distance that Tom travelled in 3 h
= 3 x 51
= 153 km
Remaining distance that Tom needed to travel
= 339 - 153
= 186 km
Time that Tom needed to reach his destination after the two met
= 186 ÷ 51
= 3
3351 = 3
1117 h
Answer(s): (a) 62 km/h; (b) 3
1117 h