City N and City P are 410 km apart. At 2.23 p.m., Andy is travelling at a uniform speed left City N for City P while Valen set off from City P to City N along the same road at a uniform speed, which was 5 km/h slower than that of Andy. The two met at 4.23 p.m.
- Find the speed of Andy.
- If Valen continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Andy and Valen to travel from 2.23 p.m. to 4.23 p.m. = 2 h
Average speed of Andy and Valen
= 410 ÷ 2
= 205 km/h
Andy's speed
= (205 + 5) ÷ 2
= 210 ÷ 2
= 105 km/h
(b)
Valen's speed
= 105 - 5
= 100 km/h
Distance that Valen travelled in 2 h
= 2 x 100
= 200 km
Remaining distance that Valen needed to travel
= 410 - 200
= 210 km
Time that Valen needed to reach his destination after the two met
= 210 ÷ 100
= 2
10100 = 2
110 h
Answer(s): (a) 105 km/h; (b) 2
110 h