City B and City C are 399 km apart. At 3.48 p.m., Bryan is travelling at a uniform speed left City B for City C while Julian set off from City C to City B along the same road at a uniform speed, which was 7 km/h slower than that of Bryan. The two met at 6.48 p.m.

1. Find the speed of Bryan.
2. If Julian continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.

(a)
Time taken for Bryan and Julian to travel from 3.48 p.m. to 6.48 p.m. = 3 h

Average speed of Bryan and Julian
= 399 ÷ 3
= 133 km/h

Bryan's speed
= (133 + 7) ÷ 2
= 140 ÷ 2 
= 70 km/h

(b)
Julian's speed
= 70 - 7
= 63 km/h

Distance that Julian travelled in 3 h
= 3 x 63
= 189 km

Remaining distance that Julian needed to travel
= 399 - 189
= 210 km

Time that Julian needed to reach his destination after the two met
= 210 ÷ 63
= 3²¹₆₃
= 3¹₃ h

Answer(s): (a) 70 km/h; (b) 3¹₃ h