City F and City G are 558 km apart. At 5.26 p.m., Gabriel is travelling at a uniform speed left City F for City G while Billy set off from City G to City F along the same road at a uniform speed, which was 6 km/h slower than that of Gabriel. The two met at 8.26 p.m.
- Find the speed of Gabriel.
- If Billy continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Gabriel and Billy to travel from 5.26 p.m. to 8.26 p.m. = 3 h
Average speed of Gabriel and Billy
= 558 ÷ 3
= 186 km/h
Gabriel's speed
= (186 + 6) ÷ 2
= 192 ÷ 2
= 96 km/h
(b)
Billy's speed
= 96 - 6
= 90 km/h
Distance that Billy travelled in 3 h
= 3 x 90
= 270 km
Remaining distance that Billy needed to travel
= 558 - 270
= 288 km
Time that Billy needed to reach his destination after the two met
= 288 ÷ 90
= 3
1890 = 3
15 h
Answer(s): (a) 96 km/h; (b) 3
15 h