City Y and City Z are 408 km apart. At 2.29 p.m., Asher is travelling at a uniform speed left City Y for City Z while Henry set off from City Z to City Y along the same road at a uniform speed, which was 8 km/h slower than that of Asher. The two met at 5.29 p.m.
- Find the speed of Asher.
- If Henry continued to travel at the same speed, how long would it take for him to reach his destination after the two met? Express your answer in mixed number.
(a)
Time taken for Asher and Henry to travel from 2.29 p.m. to 5.29 p.m. = 3 h
Average speed of Asher and Henry
= 408 ÷ 3
= 136 km/h
Asher's speed
= (136 + 8) ÷ 2
= 144 ÷ 2
= 72 km/h
(b)
Henry's speed
= 72 - 8
= 64 km/h
Distance that Henry travelled in 3 h
= 3 x 64
= 192 km
Remaining distance that Henry needed to travel
= 408 - 192
= 216 km
Time that Henry needed to reach his destination after the two met
= 216 ÷ 64
= 3
2464 = 3
38 h
Answer(s): (a) 72 km/h; (b) 3
38 h